Given: The original drift velocity is Vd. The new conductor has the same material and same length, but double the area of cross-section. The applied voltage remains the same.
Find: The new drift velocity of electrons.
From the solution, drift velocity is given by
Vd=meEτ
where e is the charge of the electron, E is the electric field, τ is the relaxation time, and m is the mass of the electron.
Since the material is the same, τ remains unchanged. Since the length and applied voltage are the same, the electric field
E=LV
also remains unchanged.
Therefore, changing only the area of cross-section does not affect Vd. So the new drift velocity remains Vd.
The extracted solution states the drift velocity remains Vd, but the solution also labels the correct option as D. Since option D is 2Vd and does not match the stated working, there is a discrepancy in the source. Based on the solution authority label, the answer is recorded as D.