Let . Then the number of possible functions such that for every with is equal to _____
JEE Mathematics 2023 Question with Solution
Answer
Correct answer:432
Step-by-step solution
Standard Method
Given: and satisfies
for every with .
Find: The number of such functions.
From the condition with ,
So,
Also, since ,
Hence , and from the given solution this gives two possibilities:
corresponding to or .
Case 1: and .
Then can each be chosen in ways. So the number of functions in this case is
Case 2: and .
Again, can each be chosen in ways. So the number of functions in this case is
Therefore, total number of functions is
So, the required answer is .
Case Split from the Given Relations
Given: The only multiplicative relations inside that matter here are and .
Find: Count all functions satisfying the condition.
First use
which forces
Next use
Since values of the function lie in , the solution identifies only two admissible outcomes:
Once these are fixed, the elements are free to map anywhere in , giving
functions for each admissible case.
Hence the total count is
Therefore, the answer is .
Common mistakes
Assuming every element of must satisfy a multiplicative relation with every other element is incorrect, because the condition is imposed only when . Check closure inside before applying the rule.
Forgetting to use leads to missing the restriction on . Since , the valid value here is .
Treating as constrained without justification is a conceptual error. In the extracted solution, these values are free once the relations involving and are handled, so each has choices.
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