MCQEasyJEE Main 2023 · 30 January, Shift 2Elasticity & Stress-Strain Curve

Physics Question from JEE Main 2023 · 30 January, Shift 2

A force is applied to a steel wire ‘A’, rigidly clamped at one end. As a result, elongation in the wire is 0.2 mm0.2 \, \text{mm}. If same force is applied to another steel wire ‘B’ of double the length and a diameter 2.42.4 times that of the wire ‘A’, the elongation in the wire ‘B’ will be (wires having uniform circular cross sections):

  • A

    6.06×10−26.06 \times 10^{-2} mm\text{mm}

  • B

    2.77×10−22.77 \times 10^{-2} mm\text{mm}

  • C

    3.0×10−23.0 \times 10^{-2} mm\text{mm}

  • D

    6.9×10−26.9 \times 10^{-2} mm\text{mm}

Answer & step-by-step solution

Sign in to reveal the correct answer, the full step-by-step solution, and the common mistakes for this question.

Sign in to see the solution

Practice more Elasticity & Stress-Strain Curve questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.

Start free trialMore on Elasticity & Stress-Strain Curve

Related questions