JEE Chemistry 2023 Question with Solution

Given: The question asks for the energy of one mole of photons of radiation of frequency $2 \times 10^{12} \, \text{Hz}$ using $h = 6.626 \times 10^{-34} \, \text{Js}$ and $N_A = 6.022 \times 10^{23} \, \text{mol}^{-1}$.

Find: Energy in $\text{J mol}^{-1}$.

The solution is for a completely different question about molarity and strength in $\text{gm/L}$, and concludes with 150. It is unrelated to the photon-energy question, so a valid worked solution cannot be extracted from the solution.

The answer key states $798 \, \text{J mol}^{-1}$, but because the authoritative the solution is unrelated, the extracted answer cannot be resolved with certainty from the provided materials.