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JEE Chemistry 2023 Question with Solution

Match List I with List II

A matching table with List-I containing entries A, B, C, D and List-II containing items I, II, III, IV to be matched accordingly.

Choose the correct answer from the options given below:

  • A

    A – II, B – III, C – IV, D – I

  • B

    A – IV, B – III, C – II, D – I

  • C

    A – II, B – I, C – IV, D – III

  • D

    A – IV, B – I, C – II, D – III

Answer

Correct answer:A

Step-by-step solution

Standard Method

Given: A matching question between physical quantities in List I and their dimensions in List II.

Find: The correct matching and hence the correct option.

From the solution:

  • A: Torque ⇒\Rightarrow IV : kg m2 s−2\mathrm{kg\, m^2\, s^{-2}}
  • B: Energy density ⇒\Rightarrow I : kg m−1 s−2\mathrm{kg\, m^{-1}\, s^{-2}}
  • C: Pressure gradient ⇒\Rightarrow III : kg m−2 s−2\mathrm{kg\, m^{-2}\, s^{-2}}
  • D: Impulse ⇒\Rightarrow II : kg m s−1\mathrm{kg\, m\, s^{-1}}

Therefore the matching is A-IV, B-I, C-III, D-II.

So, the correct option according to the solution is A.

Common mistakes

  • Confusing torque with force. Torque has dimensions of force ×\times distance, so it is kg m2 s−2\mathrm{kg\, m^2\, s^{-2}}, not the dimensions of force alone.

  • Treating energy density as energy instead of energy per unit volume. Divide the dimensions of energy by volume to get kg m−1 s−2\mathrm{kg\, m^{-1}\, s^{-2}}.

  • Mixing up pressure and pressure gradient. Pressure gradient means pressure per unit length, so one extra power of m−1m^{-1} appears.

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