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JEE Mathematics 2023 Question with Solution

Match List I with List II:

A matching table with List I containing four reactions A, B, C, D and List II containing reaction types I to IV.
  • A

    A – IV, B – I, C – III, D – II

  • B

    A – I, B – II, C – IV, D – III

  • C

    A – I, B – III, C – II, D – I

  • D

    A – II, B – I, C – IV, D – III

Answer

Correct answer:D

Step-by-step solution

Standard Method

Given: A matching problem between List I and List II.

Find: The correct correspondence among the four entries.

From the provided source, the answer key states (4) A – II, B – I, C – IV, D – III. However, the solution is for a different question involving iterates of a function f1(x)=3x+22x+3f_1(x) = \frac{3x+2}{2x+3} and concludes a+b=3125a+b=3125, so it is unrelated to this matching question.

Therefore, the answer is resolved from the answer key.

The correct matching is A – II, B – I, C – IV, D – III. Hence, the correct option is D.

Common mistakes

  • Matching directly by superficial appearance of the reactions is incorrect because similar-looking aromatic transformations can belong to different named categories. Identify the reaction type from the actual reagent and change involved.

  • Ignoring the labels in List II and only comparing products is wrong. In matching questions, use both the reagent pattern and the mechanistic class before assigning the Roman numeral.

  • Marking the mapping correctly but choosing the wrong option number is a common error. After obtaining the full correspondence, compare it carefully with options A to D.

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