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MCQMediumJEE Main 2023 · 30 January, Shift 1Determinants Basics

Mathematics Question from JEE Main 2023 · 30 January, Shift 1

Let A=[mnpq], d=∣A∣≠0, and ∣A−d(Adj A)∣=0.A = \begin{bmatrix} m & n \\ p & q \end{bmatrix}, \, d = |A| \neq 0, \, \text{and } |A - d(\text{Adj } A)| = 0. Then:

  • A

    (1+d)2=(m+q)2(1 + d)^2 = (m + q)^2

  • B

    1+d2=(m+q)21 + d^2 = (m + q)^2

  • C

    (1+d)2=m2+q2(1 + d)^2 = m^2 + q^2

  • D

    1+d2=m2+q21 + d^2 = m^2 + q^2

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