NVAMediumJEE Main 2023 · 29 January, Shift 2Projectile Motion

Physics Question from JEE Main 2023 · 29 January, Shift 2

A particle of mass 100g100 \, \text{g} is projected at time t=0t = 0 with a speed of 20ms120 \, \text{ms}^{-1} at an angle 4545^\circ to the horizontal. The magnitude of the angular momentum of the particle about the starting point at time t=2st = 2 \, \text{s} is found to be Kkgm2/s\sqrt{K} \, \text{kgm}^2/\text{s}. The value of KK is:

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