MCQEasyJEE Main 2023 · 29 January, Shift 2Uniform Circular Motion

Physics Question from JEE Main 2023 · 29 January, Shift 2

An object moves at a constant speed along a circular path in a horizontal plane with the center at the origin. When the object is at x=+2 mx = +2 \, m, its velocity is −4j^ m/s-4\hat{j} \, m/s. The object's velocity (vv) and acceleration (aa) at x=−2 mx = -2 \, m will be:

  • A

    v=4i^ m/s, a=8j^ m/s2v = 4\hat{i} \, m/s, \, a = 8\hat{j} \, m/s^2

  • B

    v=4j^ m/s, a=8i^ m/s2v = 4\hat{j} \, m/s, \, a = 8\hat{i} \, m/s^2

  • C

    v=−4j^ m/s, a=8i^ m/s2v = -4\hat{j} \, m/s, \, a = 8\hat{i} \, m/s^2

  • D

    v=−4i^ m/s, a=−8j^ m/s2v = -4\hat{i} \, m/s, \, a = -8\hat{j} \, m/s^2

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