Let be a relation defined on as if is a multiple of . Then is:
- A
not reflexive
- B
transitive but not symmetric
- C
symmetric but not transitive
- D
an equivalence relation
Let be a relation defined on as if is a multiple of . Then is:
not reflexive
transitive but not symmetric
symmetric but not transitive
an equivalence relation
Correct answer:B
Standard Method
Given: is defined on by if is a multiple of .
Find: Which property combination the relation satisfies.
From the solution:
Reflexivity:
Since is a multiple of , is reflexive.
Symmetry:
The solution states that both are satisfied, so is symmetric.
Transitivity:
Adding, the solution gives
so . Thus, is transitive.
Therefore, the working in the solution concludes that the relation is reflexive, symmetric, and transitive, which would make it an equivalence relation. However, the solution explicitly declares the correct option as B. Following the solution's authority for the final marked answer, the correct option is B.
Answer Resolution from Source
The solution contains an internal inconsistency:
Because the solution's explicitly labels B as correct, the extracted answer is recorded as B, while preserving the discrepancy in the solution content.
Checking only one property, such as reflexivity, and concluding the answer from that alone is incorrect. A relation must be tested separately for reflexivity, symmetry, and transitivity.
Assuming that automatically implies without comparing and can lead to a wrong conclusion. Symmetry must be verified from the defining condition.
In transitivity, students often add the two given equations carelessly and fail to isolate correctly. The target expression must match the original relation definition.
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