MCQMediumJEE Main 2023 · 29 January, Shift 2Middle Term

Mathematics Question from JEE Main 2023 · 29 January, Shift 2

Let KK be the sum of the coefficients of the odd powers of xx in the expansion of (1+x)99(1+x)^{99}. Let aa be the middle term in the expansion of (2+12)200\left(2 + \frac{1}{\sqrt{2}}\right)^{200}. If 200C99Ka=2mn,\frac{^{200}C_{99}K}{a} = \frac{2^\ell m}{n}, where mm and nn are odd numbers, then the ordered pair (,n)(\ell, n) is equal to:

  • A

    (50,51)(50, 51)

  • B

    (51,99)(51, 99)

  • C

    (50,101)(50, 101)

  • D

    (51,101)(51, 101)

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