NVAMediumJEE Main 2023 · 29 January, Shift 1Colligative Properties

Chemistry Question from JEE Main 2023 · 29 January, Shift 1

Solid lead nitrate is dissolved in 1 litre1 \, \text{litre} of water. The solution was found to boil at 100.15∘C100.15^\circ \text{C}. When 0.2 mol0.2 \, \text{mol} of NaCl is added to the resulting solution, it was observed that the solution froze at −0.8∘C-0.8^\circ \text{C}. The solubility product of PbCl2\text{PbCl}_2 formed is _____ ×10−6\times 10^{-6} at 298 K298 \, \text{K} (Nearest integer).

Given: Kb=0.5 K kg mol−1K_b = 0.5 \, \text{K kg mol}^{-1}, Kf=1.8 kg mol−1K_f = 1.8 \, \text{kg mol}^{-1}

Answer & step-by-step solution

Sign in to reveal the correct answer, the full step-by-step solution, and the common mistakes for this question.

Sign in to see the solution

Practice more Colligative Properties questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.

Start free trialMore on Colligative Properties

Related questions