MCQEasyJEE 2023Qualitative Analysis (N, S, Halogens)

JEE Chemistry 2023 Question with Solution

Compound that will give positive Lassaigne's test for both nitrogen and halogen is:

  • A

    N2H4HCl\mathrm{N_2H_4\cdot HCl}

  • B

    CH3NH2HCl\mathrm{CH_3NH_2\cdot HCl}

  • C

    NH4Cl\mathrm{NH_4Cl}

  • D

    NH2OHHCl\mathrm{NH_2OH\cdot HCl}

Answer

Correct answer:A

Step-by-step solution

Standard Method

Given: We need to identify the compound that gives a positive Lassaigne's test for both nitrogen and halogen.

Find: Which option contains the required features for detection in Lassaigne's test.

Lassaigne's test detects nitrogen, sulfur, and halogens in organic compounds. On sodium fusion, nitrogen is converted to NaCN\mathrm{NaCN} and halogen is converted to NaX\mathrm{NaX} where X=Cl,Br,I\mathrm{X = Cl, Br, I}.

Checking the options from the provided solution:

  1. N2H4HCl\mathrm{N_2H_4\cdot HCl}: Contains nitrogen but no halogen.
  2. CH3NH2HCl\mathrm{CH_3NH_2\cdot HCl}: Contains both nitrogen and halogen.
  3. NH4Cl\mathrm{NH_4Cl}: Contains nitrogen and halogen but is not an organic compound.
  4. NH2OHHCl\mathrm{NH_2OH\cdot HCl}: Contains nitrogen and halogen but does not form the required products in Lassaigne's test.

Therefore, only CH3NH2HCl\mathrm{CH_3NH_2\cdot HCl} gives a positive Lassaigne's test for both nitrogen and halogen.

The solution concludes the compound is option (2), which corresponds to B, but the page also shows "The Correct Option is A". Based on the worked conclusion and final answer line, the defensible answer is B.

Common mistakes

  • Assuming that merely having nitrogen and chlorine anywhere in the formula is sufficient. Lassaigne's test is applied to organic compounds, so inorganic salts like NH4Cl\mathrm{NH_4Cl} are not taken as correct here.

  • Trusting the displayed option letter without checking the worked explanation. Here the solution heading says A, but the detailed conclusion clearly identifies option (2), so the content must be reconciled using the explanation.

  • Ignoring that the test depends on formation of the required sodium-fusion products. A compound may contain the elements yet still not satisfy the test conditions as explained for NH2OHHCl\mathrm{NH_2OH\cdot HCl}.

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