Jeeify
MCQMediumJEE Main 2023 · 29 January, Shift 1Satellites & Orbital Velocity

Physics Question from JEE Main 2023 · 29 January, Shift 1

Two particles of equal mass mm move in a circle of radius rr under the action of their mutual gravitational attraction. The speed of each particle will be:

  • A

    GM2r\sqrt{\frac{GM}{2r}}

  • B

    4GMr\sqrt{\frac{4GM}{r}}

  • C

    GMr\sqrt{\frac{GM}{r}}

  • D

    GM4r\sqrt{\frac{GM}{4r}}

Answer & step-by-step solution

Sign in to reveal the correct answer, the full step-by-step solution, and the common mistakes for this question.

Sign in to see the solution

Practice more Satellites & Orbital Velocity questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.

Start free trialMore on Satellites & Orbital Velocity

Related questions