MCQMediumJEE Main 2023 · 29 January, Shift 1Cross Product

Mathematics Question from JEE Main 2023 · 29 January, Shift 1

Let the coordinates of one vertex of triangle ABC be A(0,2,α)A(0, 2, \alpha) and the other two vertices lie on the line x+α5=y12=z+43\frac{x + \alpha}{5} = \frac{y - 1}{2} = \frac{z + 4}{3}. For αZ\alpha \in \mathbb{Z}, if the area of triangle ABC is 2121 square units and the line segment BC has length 2212\sqrt{21} units, then α2\alpha^2 is equal to:

  • A

    99

  • B

    1616

  • C

    2525

  • D

    3636

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