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MCQMediumJEE Main 2023 · 29 January, Shift 1Separation of Variables

Mathematics Question from JEE Main 2023 · 29 January, Shift 1

Let y=f(x)y = f(x) be the solution of the differential equation y(x+1) dx−x2 dy=0y(x + 1) \, dx - x^2 \, dy = 0, y(1)=ey(1) = e. Then lim⁡x→0+f(x)\lim_{x \to 0^+} f(x) is equal to:

  • A

    00

  • B

    1e\frac{1}{e}

  • C

    e2e^2

  • D

    1e2\frac{1}{e^2}

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