MCQMediumJEE 2023Dot Product

JEE Mathematics 2023 Question with Solution

If the vectors a=λi^+μj^+4k^\mathbf{a} = \lambda \hat{i} + \mu \hat{j} + 4\hat{k}, b=2i^+4j^2k^\mathbf{b} = -2\hat{i} + 4\hat{j} - 2\hat{k}, and c=2i^+3j^+k^\mathbf{c} = 2\hat{i} + 3\hat{j} + \hat{k} are coplanar, and the projection of a\mathbf{a} on vector b\mathbf{b} is 54\sqrt{54} units, then the sum of all possible values of λ+μ\lambda + \mu is equal to:

  • A

    00

  • B

    66

  • C

    2424

  • D

    1818

Answer

Correct answer:A

Step-by-step solution

Standard Method

Given:

  • a=λi^+μj^+4k^\mathbf{a} = \lambda \hat{i} + \mu \hat{j} + 4\hat{k}
  • b=2i^+4j^2k^\mathbf{b} = -2\hat{i} + 4\hat{j} - 2\hat{k}
  • c=2i^+3j^+k^\mathbf{c} = 2\hat{i} + 3\hat{j} + \hat{k}
  • Projection of a\mathbf{a} on b\mathbf{b} is 54\sqrt{54}
  • The vectors are coplanar

Find: The sum of all possible values of λ+μ\lambda + \mu.

From the solution, coplanarity gives

a(b×c)=0\mathbf{a} \cdot (\mathbf{b} \times \mathbf{c}) = 0

and the projection formula gives

abb=54\frac{\mathbf{a} \cdot \mathbf{b}}{|\mathbf{b}|} = \sqrt{54}

The dot product shown is

ab=(λi^+μj^+4k^)(2i^+4j^2k^)\mathbf{a} \cdot \mathbf{b} = (\lambda \hat{i} + \mu \hat{j} + 4\hat{k}) \cdot (-2\hat{i} + 4\hat{j} - 2\hat{k})

so

ab=2λ+4μ8\mathbf{a} \cdot \mathbf{b} = -2\lambda + 4\mu - 8

Also,

b=(2)2+42+(2)2=24=26|\mathbf{b}| = \sqrt{(-2)^2 + 4^2 + (-2)^2} = \sqrt{24} = 2\sqrt{6}

Substituting into the projection relation,

2λ+4μ826=54\frac{-2\lambda + 4\mu - 8}{2\sqrt{6}} = \sqrt{54}

the solution then simplifies this using

54=36\sqrt{54} = 3\sqrt{6}

and states

2λ+4μ8=66-2\lambda + 4\mu - 8 = 6\sqrt{6}

Using the coplanarity condition together with this equation, the solution concludes that

λ+μ=24\lambda + \mu = 24

Therefore, the source solution concludes that the required value corresponds to option A.

However, the solution's is internally inconsistent: the question block marks (3)  24(3)\;24, while the solution says A, and the worked conclusion states λ+μ=24\lambda + \mu = 24. Since the worked conclusion gives the numerical result 2424, the defensible option from the listed choices is C.

Consistency Check from the Worked Conclusion

Given: The source solution explicitly concludes λ+μ=24\lambda + \mu = 24.

Find: Which option matches that value.

Comparing with the options:

  • A = 00
  • B = 66
  • C = 2424
  • D = 1818

So the numerical conclusion in the working matches option C.

This shows the header statement "The Correct Option is A" is inconsistent with the actual worked result. Therefore, using the worked conclusion as the authority, the correct option should be C.

Common mistakes

  • Using only the projection condition and ignoring coplanarity. That leaves two variables with insufficient valid information. Use both the projection relation and the scalar triple product condition together.

  • Confusing projection with dot product. The projection of a\mathbf{a} on b\mathbf{b} is abb\frac{\mathbf{a}\cdot\mathbf{b}}{|\mathbf{b}|}, not merely ab\mathbf{a}\cdot\mathbf{b}.

  • Making an error in the magnitude of b\mathbf{b}. Since b=(2,4,2)\mathbf{b} = (-2,4,-2), its magnitude is 4+16+4=24=26\sqrt{4+16+4} = \sqrt{24} = 2\sqrt{6}, not 20\sqrt{20} or 66.

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