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MCQMediumJEE Main 2023 · 29 January, Shift 1Applications of Integrals (Area)

Mathematics Question from JEE Main 2023 · 29 January, Shift 1

Let A={(x,y)∈R2:y≥0,  2x≤y≤4−(x−1)2}A = \left\{(x, y) \in \mathbb{R}^2 : y \ge 0,\; 2x \le y \le \sqrt{4 - (x - 1)^2}\right\} and B={(x,y)∈R2:0≤y≤min⁡{2x,  4−(x−1)2}}B = \left\{(x, y) \in \mathbb{R}^2 : 0 \le y \le \min\left\{2x,\; \sqrt{4 - (x - 1)^2}\right\}\right\}. Then the ratio of the area of A to the area of B is:

  • A

    (π−1)/(π+1)(\pi-1)/(\pi+1)

  • B

    π/(π−1)\pi/(\pi-1)

  • C

    π/(π+1)\pi/(\pi+1)

  • D

    (π+1)/(π−1)(\pi+1)/(\pi-1)

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