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MCQEasyJEE Main 2023 · 25 January, Shift 2Gauss's Law Applications

Physics Question from JEE Main 2023 · 25 January, Shift 2

Match List I with List II

List IList II
(A) Gauss's Law in Electrostatics(I) ∮E⃗⋅dl⃗=−dΦBdt\oint \vec{E}\cdot d\vec{l} = -\dfrac{d\Phi_B}{dt}
(B) Faraday's Law(II) ∮B⃗⋅dA⃗=0\oint \vec{B}\cdot d\vec{A} = 0
(C) Gauss's Law in Magnetism(III) ∮B⃗⋅dl⃗=μ0iC+μ0ε0dΦEdt\oint \vec{B}\cdot d\vec{l} = \mu_0 i_C + \mu_0\varepsilon_0 \dfrac{d\Phi_E}{dt}
(D) Ampere–Maxwell Law(IV) ∮E⃗⋅ds⃗=qε0\oint \vec{E}\cdot d\vec{s} = \dfrac{q}{\varepsilon_0}

Choose the correct answer from the options given below:

  • A

    A-IV, B-I, C-II, D-III

  • B

    A-I, B-II, C-III, D-IV

  • C

    A-III, B-IV, C-I, D-II

  • D

    A-II, B-III, C-IV, D-I

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