MCQEasyJEE Main 2023 · 25 January, Shift 2Heat, Temperature & Thermal Expansion

Physics Question from JEE Main 2023 · 25 January, Shift 2

The graph between two temperature scales PP and QQ is shown in the figure. Between the upper fixed point and lower fixed point, there are 150150 equal divisions of scale PP and 100100 divisions on scale QQ. The relationship for conversion between the two scales is given by:

Graph of temperature on scale Q along horizontal axis and scale P along vertical axis, showing a straight line with vertical difference ΔtP = 150° and horizontal difference ΔtQ = 100° up to marked value 180 on P scale.
  • A

    tq/150=(tp180)/100t_q/150 = (t_p - 180)/100

  • B

    tq/100=(tp30)/150t_q/100 = (t_p - 30)/150

  • C

    tp/180=(tQ40)/100t_p/180 = (t_Q - 40)/100

  • D

    tp/100=(tQ180)/150t_p/100 = (t_Q - 180)/150

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