MCQMediumJEE Main 2023 · 25 January, Shift 2Functions

Mathematics Question from JEE Main 2023 · 25 January, Shift 2

Let f:RRf: \mathbb{R} \to \mathbb{R} be a function defined by f(x)=logm(2(sinxcosx)+m2)f(x) = \log_{\sqrt{m}}{\left(\sqrt{2}(\sin x - \cos x) + m - 2\right)}, for some mm, such that the range of ff is [0,2][0, 2]. Then the value of mm is:

  • A

    55

  • B

    33

  • C

    22

  • D

    44

Answer & step-by-step solution

Sign in to reveal the correct answer, the full step-by-step solution, and the common mistakes for this question.

Practice more Functions questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.

Related questions