The equations of two sides of a variable triangle are and , and its third side is a tangent to the parabola . The locus of its circumcentre is:
- A
- B
- C
- D
The equations of two sides of a variable triangle are and , and its third side is a tangent to the parabola . The locus of its circumcentre is:
Correct answer:C
Standard Method
Given: Two sides of the triangle are and . The third side is a tangent to the parabola .
Find: The locus of the circumcentre of the triangle.
For the parabola , we have
so
A tangent to in slope form is
Hence here the tangent is
with .

This tangent meets at
and meets at
Since the two given sides are perpendicular, the triangle is right-angled at . Therefore, its circumcentre is the midpoint of the hypotenuse.
So if the circumcentre is , then
Now eliminate using the given relation from the solution:
which gives
Therefore,
Replacing by , the locus is
Therefore, the correct option is C.
Using midpoint of hypotenuse
Given: The triangle is formed by the lines , , and a tangent to .
Find: The locus of the circumcentre.
The intersection of and is , so the angle between these two sides is a right angle.
Let the tangent be
Then its intercept on is
and its intercept on is found from
so
and hence
Thus
The hypotenuse is , so the circumcentre is its midpoint:
Eliminating gives
So the locus of the circumcentre is the parabola represented by this equation.
Therefore, the correct option is C.
Treating the circumcentre as the intersection of angle bisectors without using the right-triangle property is inefficient here. Since and are perpendicular, the triangle is right-angled, so the circumcentre is the midpoint of the hypotenuse.
Using the wrong tangent form for is a common error. The slope form is , not a tangent form from another conic. Here , so the tangent is .
While finding the intersection with , students often make an algebraic mistake in solving for . Substitute carefully into the tangent equation and isolate before taking the midpoint.
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