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MCQEasyJEE 2023Salt Analysis (Cations & Anions)

JEE Chemistry 2023 Question with Solution

Match the List-I with List-II:

A matching table with List-I and List-II entries for continuity and differentiability question, containing items P, Q, R, S and options i, ii, iii, iv.
  • A

    P→\to i, Q→\to iii, R→\to ii, S→\to iv

  • B

    P→\to iv, Q→\to ii, R→\to iii, S→\to i

  • C

    P→\to iii, Q→\to i, R→\to iv, S→\to ii

  • D

    P→\to i, Q→\to iii, R→\to iv, S→\to ii

Answer

Correct answer:D

Step-by-step solution

Standard Method

Given: Match the cations in List-I with the corresponding group reagents in List-II.

From qualitative analysis:

  • Pb2+^{2+}, Cu2+^{2+} are precipitated by H2_2S in presence of dilute HCl.
  • Al3+^{3+}, Fe3+^{3+} are precipitated by NH4_4OH in presence of NH4_4Cl.
  • Co2+^{2+}, Ni2+^{2+} are precipitated by H2_2S in presence of NH4_4OH.
  • Ba2+^{2+}, Ca2+^{2+} are precipitated by (NH4_4)2_2CO3_3 in presence of NH4_4OH.

Find: The correct matching.

Thus,

  • P →\to i
  • Q →\to iii
  • R →\to iv
  • S →\to ii

Therefore, the correct option is D.

Common mistakes

  • Confusing the reagent for Group II and Group IV cations is a common mistake. H2_2S in acidic medium identifies Group II, while H2_2S in ammoniacal medium identifies Group IV. Always check the medium carefully.

  • Students often interchange Al3+^{3+}, Fe3+^{3+} with Ba2+^{2+}, Ca2+^{2+}. This is incorrect because Al3+^{3+}, Fe3+^{3+} are grouped with NH4_4OH/NH4_4Cl, whereas Ba2+^{2+}, Ca2+^{2+} are precipitated using (NH4_4)2_2CO3_3 in ammoniacal medium.

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