MCQEasyJEE 2023Characteristics of EM Waves

JEE Physics 2023 Question with Solution

An electromagnetic wave is transporting energy in the negative zz-direction. At a certain point and certain time, the direction of the electric field of the wave is along the positive yy-direction. What will be the direction of the magnetic field at that point and instant?

  • A

    Positive direction of xx

  • B

    Negative direction of xx

  • C

    Negative direction of yy

  • D

    Negative direction of zz

Answer

Correct answer:A

Step-by-step solution

Using the Poynting vector direction

Given: Energy transport is in the negative zz-direction, so the Poynting vector is along k^-\hat{k}. The electric field is along the positive yy-direction, so E=+j^\vec{E} = +\hat{j}.

Find: The direction of the magnetic field.

For an electromagnetic wave, the direction of energy flow is given by the Poynting vector:

S=E×H\vec{S} = \vec{E} \times \vec{H}

Substitute the given directions:

k^=(+j^)×H-\hat{k} = (+\hat{j}) \times \vec{H}

Using the right-hand rule, we need a vector H\vec{H} such that

j^×H=k^\hat{j} \times \vec{H} = -\hat{k}

Since

j^×i^=k^\hat{j} \times \hat{i} = -\hat{k}

the magnetic field must be along +i^+\hat{i}, that is, the positive xx-direction.

Therefore, the magnetic field is in the positive direction of xx. The correct option is A.

The solution contains an inconsistency because it labels the correct option as C, but the worked vector relation and concluding statement both support positive direction of xx.

Right-hand triad check

Given: E\vec{E} is along +j^+\hat{j} and energy flow is along k^-\hat{k}.

Find: The direction of H\vec{H}.

In an electromagnetic wave, E\vec{E}, H\vec{H}, and the direction of propagation form a right-handed set with

E×H=S\vec{E} \times \vec{H} = \vec{S}

So choose the magnetic field direction so that

j^×H=k^\hat{j} \times \vec{H} = -\hat{k}

This is satisfied by H=+i^\vec{H} = +\hat{i}.

Hence, the magnetic field points in the positive xx-direction.

Common mistakes

  • Using the incorrect cross-product order as H×E\vec{H} \times \vec{E}. This reverses the direction of the Poynting vector. Always use S=E×H\vec{S} = \vec{E} \times \vec{H}.

  • Confusing the option label with the actual worked answer. The solution marks option C, but its vector calculation and final statement give positive xx-direction. Always trust the consistent physics working.

  • Applying the right-hand rule incorrectly for unit vectors. Remember that i^×j^=k^\hat{i} \times \hat{j} = \hat{k}, so reversing the order changes the sign.

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