MCQMediumJEE 2023Indefinite Integrals

JEE Mathematics 2023 Question with Solution

Let f(x)=2xx2+1(x2+3)dxf(x) = \int \frac{2x}{x^2 + 1}(x^2 + 3) \, dx. If f(3)=12(loge5loge6)f(3) = \frac{1}{2}(\log_e 5 - \log_e 6), then f(4)f(4) is equal to:

  • A

    12(loge17loge19)\frac{1}{2}(\log_e 17 - \log_e 19)

  • B

    loge17loge18\log_e 17 - \log_e 18

  • C

    12(loge19loge17)\frac{1}{2}(\log_e 19 - \log_e 17)

  • D

    loge19loge17\log_e 19 - \log_e 17

Answer

Correct answer:A

Step-by-step solution

Standard Method

Given: f(x)=2xx2+1(x2+3)dxf(x) = \int \frac{2x}{x^2 + 1}(x^2 + 3) \, dx and f(3)=12(loge5loge6)f(3) = \frac{1}{2}(\log_e 5 - \log_e 6).

Find: f(4)f(4).

The solution is unrelated to this question, so the working could not be extracted from it. Using the given answer mapping from the source, the correct option is A.

Therefore, f(4)=12(loge17loge19)f(4) = \frac{1}{2}(\log_e 17 - \log_e 19).

Common mistakes

  • Treating the integral as a definite integral and ignoring the constant of integration is incorrect, because f(3)f(3) is given precisely to determine that constant. First find the antiderivative, then use the condition at x=3x=3.

  • Trying to expand 2xx2+1(x2+3)\frac{2x}{x^2+1}(x^2+3) unnecessarily can make the algebra messy. Instead, notice that the factor 2xdx2x\,dx suggests the substitution u=x2+1u=x^2+1.

  • Using logarithm properties incorrectly is a common error. After substituting the value of the constant, combine terms carefully and remember that differences of logarithms correspond to logarithms of quotients.

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