MCQMediumJEE Main 2023 · 25 January, Shift 1Cross Product

Mathematics Question from JEE Main 2023 · 25 January, Shift 1

Let a,b,c\vec{a}, \vec{b}, \vec{c} be three non-zero vectors such that bc=0\vec{b} \cdot \vec{c} = 0 and a×(b×c)=bc2\vec{a} \times (\vec{b} \times \vec{c}) = \frac{\vec{b} - \vec{c}}{2}. If d\vec{d} is a vector such that bd=ab\vec{b} \cdot \vec{d} = \vec{a} \cdot \vec{b}, then (a×b)(c×d)(\vec{a} \times \vec{b}) \cdot (\vec{c} \times \vec{d}) is equal to:

  • A

    11

  • B

    14\frac{1}{4}

  • C

    22

  • D

    12\frac{1}{2}

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