The value of the integral: ∫_(3√2/4)^(3√3/4) 48/√(9 - 4x²) dx is… | JEE Main 2023 Mathematics PYQ | Jeeify

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MCQMediumJEE Main 2023 · 24 January, Shift 2Definite Integrals

The value of the integral: $\int_{\frac{3\sqrt{2}}{4}}^{\frac{3\sqrt{3}}{4}} \frac{48}{\sqrt{9 - 4x^2}} \, dx$ is equal to:

A
$\frac{\pi}{3}$
B
$\frac{\pi}{2}$
C
$\frac{\pi}{6}$
D
$2\pi$

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