MCQMediumJEE Main 2023 · 24 January, Shift 2Separation of Variables

Mathematics Question from JEE Main 2023 · 24 January, Shift 2

Let y=y(x)y = y(x) be the solution of the differential equation (x23y2)dx+3xydy=0,y(1)=1.(x^2 - 3y^2)dx + 3xy \, dy = 0, \quad y(1) = 1. Then 6y2(e)6y^2(e) is equal to:

  • A

    3e23e^2

  • B

    e2e^2

  • C

    2e22e^2

  • D

    3e22\frac{3e^2}{2}

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