MCQEasyJEE 2023Lanthanides & Actinides

JEE Chemistry 2023 Question with Solution

Which one amongst the following are good oxidizing agents? A. Sm2+Sm^{2+} B. Ce2+Ce^{2+} C. Ce4+Ce^{4+} D. Tb4+Tb^{4+}

Choose the most appropriate answer from the options given below:

  • A

    C only

  • B

    D only

  • C

    A and B only

  • D

    C and D only

Answer

Correct answer:B

Step-by-step solution

Standard Method

Given: The species are Sm2+Sm^{2+}, Ce2+Ce^{2+}, Ce4+Ce^{4+} and Tb4+Tb^{4+}.

Find: Which among them are good oxidizing agents.

A good oxidizing agent readily accepts electrons to attain a more stable oxidation state.

From the explanation:

  • Ce4+Ce^{4+} acts as a good oxidizing agent because it readily accepts electrons to attain the more stable Ce3+Ce^{3+} configuration.
  • Tb4+Tb^{4+} also acts as a good oxidizing agent because it gets reduced to the more stable Tb3+Tb^{3+} configuration.
  • Sm2+Sm^{2+} and Ce2+Ce^{2+} are reducing agents because they tend to lose electrons to attain stable configurations.

Thus, the good oxidizing agents are Ce4+Ce^{4+} and Tb4+Tb^{4+}. Therefore, the correct option is B.

Common mistakes

  • Treating Sm2+Sm^{2+} and Ce2+Ce^{2+} as oxidizing agents is incorrect because these species tend to lose electrons and behave as reducing agents. Check whether the species accepts electrons or donates them.

  • Assuming every higher oxidation state ion is automatically stable is wrong. Ce4+Ce^{4+} and Tb4+Tb^{4+} are good oxidizing agents here because they readily reduce to the more stable +3+3 state.

Practice more Lanthanides & Actinides questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step — free to start.

Related questions