Physics Question from JEE Main 2023 · 24 January, Shift 2

A spherical ball of radius $1 \, \text{mm}$ and density $10.5 \, \text{g/cc}$ is dropped in glycerine of coefficient of viscosity $9.8 \, \text{poise}$ and density $1.5 \, \text{g/cc}$. Viscous force on the ball when it attains constant velocity is $3696 \times 10^{-x} \, \text{N}$. The value of $x$ is:

(Given, $g = 9.8 \, \text{m/s}^2$ and $\pi = \frac{22}{7}$)