MCQEasyJEE Main 2023 · 24 January, Shift 2Characteristics of EM Waves

Physics Question from JEE Main 2023 · 24 January, Shift 2

The electric field and magnetic field components of an electromagnetic wave going through vacuum is described by: Ex=E0sin(kzωt)E_x = E_0 \sin (kz - \omega t) By=B0sin(kzωt)B_y = B_0 \sin (kz - \omega t) Then the correct relation between E0E_0 and B0B_0 is given by:

  • A

    kE0=ωB0kE_0 = \omega B_0

  • B

    E0B0=ωkE_0 B_0 = \omega k

  • C

    ωE0=kB0\omega E_0 = k B_0

  • D

    E0=kB0E_0 = k B_0

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