NVAEasyJEE 2023Kinetic Energy & Work-Energy Theorem

JEE Physics 2023 Question with Solution

Section – B

A spherical body of mass 2kg2 \, \text{kg} starting from rest acquires a kinetic energy of 10000J10000 \, \text{J} at the end of **55**th second. The force acted on the body is _____ N\text{N}.

Answer

Correct answer:40

Step-by-step solution

Standard Method

Given: Mass of the spherical body is 2kg2 \, \text{kg}. It starts from rest, so u=0u = 0. The kinetic energy at the end of 5s5 \, \text{s} is 10000J10000 \, \text{J}.

Find: The force acting on the body.

Using kinetic energy,

12mv2=KE\frac{1}{2}mv^2 = \text{KE}

Substituting the given values,

122v2=10000\frac{1}{2} \cdot 2 \cdot v^2 = 10000 v2=10000v^2 = 10000 v=100m/sv = 100 \, \text{m/s}

Now use the equation of motion,

v=u+atv = u + at

Since u=0u = 0 and t=5st = 5 \, \text{s},

100=0+a5100 = 0 + a \cdot 5 a=1005=20m/s2a = \frac{100}{5} = 20 \, \text{m/s}^2

Now the force is,

F=ma=220=40NF = ma = 2 \cdot 20 = 40 \, \text{N}

Therefore, the force acting on the body is 40N40 \, \text{N}.

Common mistakes

  • Using the kinetic energy formula incorrectly as mv2mv^2 instead of 12mv2\frac{1}{2}mv^2. This gives the wrong velocity. Always start with 12mv2=KE\frac{1}{2}mv^2 = \text{KE}.

  • Ignoring that the body starts from rest. If u0u \neq 0 is assumed, the acceleration becomes incorrect. Use u=0u = 0 exactly as stated in the question.

  • Directly substituting kinetic energy into force formulas without first finding velocity and acceleration. Force is obtained from F=maF = ma, so first determine vv from kinetic energy, then aa from kinematics.

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