Physics Question from JEE Main 2023 · 24 January, Shift 1

A network of resistors is connected to a battery of $24 \, \text{V}$ with an internal resistance of $3\Omega$. The network forms a single loop with the battery: starting from the battery, the current passes first through the parallel combination of $R_1 = 2\Omega$ and $R_2 = 2\Omega$, then through $R_3 = 2\Omega$ in series, then through the parallel combination of $R_4 = 20\Omega$ and $R_5 = 5\Omega$, and finally through $R_6 = 2\Omega$ in series back to the battery. The currents through the resistors $R_4$ and $R_5$ are $I_4$ and $I_5$ respectively. The values of $I_4$ and $I_5$ are: