MCQEasyJEE Main 2023 · 24 January, Shift 1Force on Current-Carrying Conductor

Physics Question from JEE Main 2023 · 24 January, Shift 1

Two long straight wires P and Q carrying equal currents of 10A10 \, \text{A} each were kept parallel to each other at a distance of 5cm5 \, \text{cm}. The magnitude of the magnetic force experienced by a 10cm10 \, \text{cm} length of wire P is F1F_1. If the distance between the wires is halved and the currents in them are doubled, the force F2F_2 on a 10cm10 \, \text{cm} length of wire P will be:

  • A

    8F18F_1

  • B

    10F110F_1

  • C

    F18\frac{F_1}{8}

  • D

    F110\frac{F_1}{10}

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